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12x-12=3x^2
We move all terms to the left:
12x-12-(3x^2)=0
determiningTheFunctionDomain -3x^2+12x-12=0
a = -3; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·(-3)·(-12)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{-6}=+2$
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